Question

solve the following quadratic equation:
x2-5x=2(3-2x)

Answer 1

Step-by-step explanation:

x²-5x=2(3-2x)

x²-5x=6-4x

x²-5x+4x-6=0

x²-x-6=0

x²-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3)(x+2)=0

(x-3)=0 or (x+2)=0

x=3 or x=-2

therefore the root of quadratic equations is 3 and -2.

Answer 2

$\huge\bold{Answer:-}$

★ Given :-

• x² - 5x = 2( 3 - 2x )

★ ToFind :-

• The quadratic equation and the roots of it .

★ Solution:-

⟼ x² - 5x = 2 ( 3 - 2x )

⟼ x² - 5x = 6 - 4x

⟼ x² - 5x + 4x - 6 = 0

⟼ x² - x - 6 = 0

Now, by doing middle term factorisation we get

⟼ x² - ( 3 -2 ) x - 6 = 0

⟼ x² - 3x + 2x - 6 = 0

⟼ x( x - 3 ) + 2 ( x - 3 ) = 0

⟼ ( x - 3) ( x + 2 ) = 0

so, Either ,

⟼ x - 3 = 0

⟼ x = 3

Or,

⟼ x + 2 = 0

⟼ x = -2

so, the roots of the quadratic equation are 3 , -2 .