Question

solve the following quadratic equationby factoriZation method 2x^2-x+1/8=0​

Answer 1

Answer:

$2 {x}^{2} - x + \frac{1}{8} = 0 \\ taking \: lcm \\ \frac{16 {x}^{2} - 8x + 1}{8 } = 0 \\ 16 {x}^{2} - 8x + 1 = 0 \\ 16 {x}^{2} - (4 + 4)x + 1 \\ 16 {x}^{2} - 4x - 4x + 1 \\ 4x(4x - 1) - 1(4x - 1) \\ x = \frac{1}{4} \\ hope \: it \: will \: help \: you$

Answer 2

Answer:

Step-by-step explanation: