Math, asked by sd70025, 3 months ago

Solve the following quadratic equations

Attachments:

Answers

Answered by tummakeerthana19
1

Answer:

1/2x-3 + 1/x-5 =1

x-5+2x-3/(x-5)(2x-3) =1

3x-8/2x²-10x-3x+15=1

3x-8/2x²-13x+15=1

3x-8=2x²-13x+15

2x²-13x-3x+15+8=0

2x²-16x+23=0

a=2 b=-16 c=23

D=b²-4ac=(-16)²-4(2)(23)=256-184=72

x=-b+√D/2a or -b-√D/2a

x=-(-16)+√72/2(2) or -(-16)+√72/2(2)

x=16+6√2/4 or 16-6√2/4

x=4 +3√2/2 or 4- 3√2/2

hope it helps you and don't forget to follow mè

Similar questions