Question

solve the following quadratic equations:-6x^2-2x=0​

Answer 1

Answer:

-6x²-2x=0

-2x(3x+1)=0

x = 0, -1/3

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Answer 2

Answer:

given quadratic equation is...

$- 6 {x}^{2} - 2x = 0 \\ - 2x(3x + 1) = 0$

therefore,

$- 2x = 0 \\ and \\ 3x + 1 = 0$

on solving this two equation we can get...

$- 2x = 0 \\ x = \frac{0}{ - 2} \\ x = 0$

and

$3x + 1 = 0 \\ 3x = - 1 \\ x = \frac{ - 1}{3}$

$your \: answers \: are \\ 0 \: and \: \frac{ - 1}{3}$

hope it helps to you☺️