Question

solve the following quadratic equations:

8(a+2)^2 + 18(a+2) =5​

Answer 1

Answer:

Step-by-step explanation:

8(a+2)^2+18(a+2)=5

8(a+2)^2+18(a+2)-5=0

let x = (a+2)

8x^2+18x-5=0

8x^2-2x+20x-5=0

2x(4x-1)+5(4x-1)=0

(2x+5)(4x-1)=0

2x+5=0 or 4x-1=0

2x=-5 or 4x=1

x=-5/2 or x=1/4

x=-2.5 or x=0.25

you can do this using quadratic equation formula also

hope this was helpful :)