Math, asked by GuptaBakelal, 11 months ago

Solve the following quadratic equations by
completing the square method.
i. x² + 8x – 48 – 0
ii. x2 + 11x + 24 = 0

iii.y² - 4y=1
iv. x² - 6x + 4 = 0
v. x2 + 8x + 9 = 0

vi. z2+4z-7=0

vii. t2 + 2t = t +3
viii. m2- 3m - 1 = 0

ix. 5x² - 4x - 3=0​

Answers

Answered by singhalseema03p9uwqn
0

i) Add

48

to both sides of the equation.

x

2

+

8

x

=

48

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of

b

.

(

b

2

)

2

=

(

4

)

2

Add the term to each side of the equation.

x

2

+

8

x

+

(

4

)

2

=

48

+

(

4

)

2

Simplify the equation.

Tap for more steps...

x

2

+

8

x

+

16

=

64

Factor the perfect trinomial square into

(

x

+

4

)

2

.

(

x

+

4

)

2

=

64

Solve the equation for

x

.

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