Question

Solve the following quadratic equations by completing the square method. b) 3x²+4x-15=0​

Answer 1

okk sure

I am attaching the pic

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Answer 2

Answer:

Step-by-step explanation:

Method - I :-

$3x^2 + 9x - 5x - 15 = 0$

$3x(x + 3) - 5(x + 3) = 0$

$(x + 3)(3x - 5) = 0$

$x + 3 = 0\\x = -3$        $3x - 5 = 0\\x = \frac{5}{3}$

Method - II :-

a = 3

b = 4

c = -15

the formula is in the picture below

$x = \frac{-4 ± \sqrt{4^2-4*3*(-15)}}{2*3}$

$x = \frac{-4 ± \sqrt{16 + 180}}{6}$

$x = \frac{-4 ± \sqrt{196}}{6}$

$x = \frac{-4 ± 14}{6}$

$x = \frac{-4 - 14}{6}\\\\x = \frac{-18}{6}\\\\x = -3$     $x = \frac{-4 + 14}{6}\\\\x = \frac{10}{6}\\\\x = \frac{5}{3}$

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