Question

Solve the following quadratic equations by factorisation method 3x^2-2√6x+2

Answer 1

Answer:

${3x}^{2} - 2 \sqrt{6x } + 2 \\ d = {b}^{2} - 4ac \\ (- 2 \sqrt{6}) {}^{2} - 4(3)(2) \\ 24 - 24 \\ = 0 \\ d = 0 \\ x = \frac{ - b + \sqrt{d} }{2a} \\ \frac{ - ( - 2 \sqrt{6) } + \sqrt{0} }{6} \\ \frac{2 \sqrt{6} }{6} \\ \frac{ \sqrt{6} }{3} \\ = \frac{ - b - \sqrt{d} }{2a} \\ \frac{ - ( - 2 \sqrt{6)} - \sqrt{0} }{6} \\ \frac{2 \sqrt{6 \ } }{6} \\ \frac{ \sqrt{6} }{3} = answer$

please mark as brilliant answer