Question

solve the following quadratic equations by factorisation method 3x square -x-10=0​

Answer 1

Given

$3x^{2} -x-10=0$

Solving, we get,

$3x^{2} -x-10=0$

$\implies 3x^{2} -6x+5x-10=0$

$\implies 3x(x-2)+5(x-2)=0$

$\implies (3x+5)(x-2)=0$

Now,

$3x+5=0$

$\implies 3x=-5$

$\implies \boxed{\boxed{\bold{ x = \dfrac{-5}{3}}}}}}}}}$

$x-2=0$

$\implies \boxed{\boxed{\bold{ x =2}}}}}}}}$

                                                                   

Answer 2

In elementary algebra, the quadratic formula is a formula that provides the solution(s) to a quadratic equation. There are other ways of solving a quadratic equation instead of using the quadratic formula, such as factoring (direct factoring, grouping, AC method), completing the square, graphing and others.

Given a general quadratic equation of the form

$a {x}^{2} + bx + c = 0$

with x representing an unknown, a, b and c representing constants with a ≠ 0, the quadratic formula is:

x=-b±√b²-4ac

where the plus-minus symbol "±" indicates that the quadratic equation has two solutions.Written separately, they become:

$x1 = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a}$

$x2 = \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a}$

Each of these two solutions is also called a root (or zero) of the quadratic equation. Geometrically, these roots represent the x-values at which any parabola, explicitly given as y = ax2 + bx + c, crosses the x-axis.

As well as being a formula that yields the zeros of any parabola, the quadratic formula can also be used to identify the axis of symmetry of the parabola, and the number of real zeros the quadratic equation contains.