Question

Solve the following quadratic equations by factorisation

Answer 1

Step-by-step explanation:

3x^2-√6x-√6x+2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-2)^2=0

(√3x-√2)(√3x-√2)=0

Answer 2

Answer:

x= $\frac{2}{\sqrt{6} }$

Step-by-step explanation:

The sum of roots= a+b= (2*6^0.5)/3

The product of roots= a*b= 2/3

By observation, the equation can be written as -

6x^2-(4*x*6^0.5)+4=0

Divide the equation by 6

x^2-(4x/6^0.5)+4/6=0

(x)^2-(2*(2/6^0.5)(x))+(2/6^0.5)^2  which is an expression of (a+b)^2 where a=, b=2/6^0.5

Therefore, (x-2/6^0.5)^2

And the factors are equal to (x-$\frac{2}{\sqrt{6} }$)