Question

solve the following quadratic equations by factorisation method: x2+x-(a+1)(a+2)=0
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Answer 1

Step-by-step explanation:

We have,

${x}^{2} + x - (a + 1)(a + 2) = 0$

$= > {x}^{2} + (a + 2)x - (a + 1)x - (a + 1)(a + 2) = 0$

$= > x(x + a + 2) - (a + 1)(x + a + 2) = 0$

$= > (x + a + 2)(x - a - 1) = 0$

$= > x = - (a + 2) \: \: or \: \: x = a + 1$