solve the following quadratic equations by factorisation
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2m^2-48m=50 ,2m^2-48-50=0,2m^2+2m-50m-50=0 ,2m(m+1)-50(m+1)=0,(m+1)(2m+50)=0,m+1=0and2m-50=0m=-1and2m=50/2=25,-1,25 are the root of the give quadratic equation
Lucksmi:
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Answered by
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2m(m-24)=50
= 2m2-48m-50=0(÷2)
=m2-24m-25=0
sum= -24(-25+1)
product= -25(-25×1)
=m2 +(-25+1)m-25=0
=m2-25m+1m-25=0
=m(m-25)-1(m-25)=0
=(m-25)(m-1)=0
=m-25=0, m=0+25=m=25
=m-1=0,m=0+1=m=1
Therefore, m=1 and m=25 is the answer
= 2m2-48m-50=0(÷2)
=m2-24m-25=0
sum= -24(-25+1)
product= -25(-25×1)
=m2 +(-25+1)m-25=0
=m2-25m+1m-25=0
=m(m-25)-1(m-25)=0
=(m-25)(m-1)=0
=m-25=0, m=0+25=m=25
=m-1=0,m=0+1=m=1
Therefore, m=1 and m=25 is the answer
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