Question

solve the following quadratic equations by factorisation.6x²-7x-13=0​

Answer 1

Answer:

6x²-7x-13=0

comparing with ax^2 +bx+c=0 we get

a=6, b= -7 , c= -13

Answer 2

Answer:

x = -1       ;  x = -13/6

Step-by-step explanation:

6x²-7x-13=0

(6x^2 + 6x) + (-13x - 13)

6x( x + 1 ) - 13 ( x + 1 )

(x+1) (6x-13)

Equate (x+1) and (6x-13)

x + 1 = 0  ;  6x + 13 = 0

x = -1       ;  x = -13/6