Question

solve the following quadratic equations by factorisation:x²-15x+54=0​

Answer 1

Answer:

X^2-15x+54=0

x^2-9x-6x+54=0

x(x-9)-6(x-9)=0

(x-9)(x-6)=0

x=9,6

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Answer 2

Answer:

Given :-

Equation

${x}^{2} - 15x + 54 = 0$

What to find out = Roots of equation?

Solution :-

Factorise by splitting method

$x {}^{2} - 15x + 54 = 0 \\ = x {}^{2} - 9x - 6x + 54 = 0 \\ = x(x - 9) - 6(x - 9) = 0 \\ = (x - 9)(x - 6) = 0 \\ now \: split \: it \: into \: possible \: cases \\ x - 9 = 0 \\ x - 6 = 0$

Hence, the zeroes of equation is

$x_1 = 9 \: \: and \: \: x_2 = 6$

Related term :-

Quadratic equation :A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.