Math, asked by sidpower2535, 8 months ago

Solve the following quadratic equations by factorization:
(1/x-3)+(2/x-2)=8/x;x≠0,2,3

Answers

Answered by ms9733756
1

Answer:

hey mate the equation is 5xsquare - 48x +48

Answered by topwriters
0

x = +4, +12/5

Step-by-step explanation:

x≠0,2,3

(1/x-3)+(2/x-2)=8/x

x (1/x-3)+ x(2/x-2) =8  

x/(x-3) + 2x/(x-2) = 8

x(x-2) + 2x(x-3) = 8 (x-2)(x-3)

x² - 2x + 2x² - 6x = 8x² -40x + 48

5x² - 32x +48 = 0

5x² - 20x -12x +48 = 0

 5x(x - 4) -12 (x - 4) = 0

 (5x -12)(x-4) = 0

 Therefore x = +4, +12/5

Similar questions