Question

Solve the following quadratic equations by factorization method.

Answer 1

HELLO DEAR,

a²b²x² - (a² + b²)x + 1 = 0

a²b²x² - a²x - b²x + 1 = 0

a²x(b²x - 1) - 1(b²x - 1) = 0

(a²x - 1)(b²x - 1) = 0

x = 1/a² , x = 1/b²

I HOPE ITS HELP YOU DEAR,

THANKS

Answer 2

Given Quadratic equation ,

a²b²x² - ( a² + b² ) x + 1 = 0

=> a²b²x² - a²x - b²x + 1 = 0

=> a²x( b²x - 1 ) - 1( b²x - 1 ) = 0

=> ( b²x - 1 ) ( a²x - 1 ) = 0

Therefore ,

b²x - 1 = 0 or a²x - 1 = 0

b²x = 1 or a²x = 1

x = 1/b² or x = 1/a²

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