solve the following quadratic equations by using formula method
1)a(x²+1)=x(a²+1)
2)x²+x-(a-2)(a+1)=0
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Given, a(x2 + 1) - x(a2 + 1)
= ax2 + a - xa2 - x
= ax2 - xa2 - x + a
= ax(x - a) - 1(x - a)
= (x - a)*(ax - 1)
To find roots, we have to equate (x - a) = 0 and (ax - 1) = 0
So, x - a = 0 and ax - 1 = 0
=> x = a, ax = 1
=> x = a, 1/a
So, the roots are a and 1/a
= ax2 + a - xa2 - x
= ax2 - xa2 - x + a
= ax(x - a) - 1(x - a)
= (x - a)*(ax - 1)
To find roots, we have to equate (x - a) = 0 and (ax - 1) = 0
So, x - a = 0 and ax - 1 = 0
=> x = a, ax = 1
=> x = a, 1/a
So, the roots are a and 1/a
CleverInvester57:
solve the sum by formula method
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