solve the following quadratic equations find value of x
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Answered by
3
Hi there !!
Here's your answer
Given,
To find the value of x in the quadratic equation,
x² - 3✓3x + 6 = 0
This can be done by the method of splitting of the middle term
so,
x² - 2✓3 x - ✓3x + 6 = 0
Taking out common factors,
x(x - 2✓3) - ✓3(x - 2✓3) = 0
So,
(x - ✓3)(x - 2✓3) = 0
x - ✓3 = 0
x = ✓3 ____(i)
and
x - 2✓3 = 0
x = 2✓3
Thus,
x = ✓3 and 2✓3
Here's your answer
Given,
To find the value of x in the quadratic equation,
x² - 3✓3x + 6 = 0
This can be done by the method of splitting of the middle term
so,
x² - 2✓3 x - ✓3x + 6 = 0
Taking out common factors,
x(x - 2✓3) - ✓3(x - 2✓3) = 0
So,
(x - ✓3)(x - 2✓3) = 0
x - ✓3 = 0
x = ✓3 ____(i)
and
x - 2✓3 = 0
x = 2✓3
Thus,
x = ✓3 and 2✓3
Answered by
1
x^2 - 3√3x +6 = 0
x^2 - √3x - 2√3x + 6 = 0
x(x-√3)-2√3(x-√3) =0
(x-2√3)(x-√3) =0
x = 2√3 or x = √3
Hope it helps.
x^2 - √3x - 2√3x + 6 = 0
x(x-√3)-2√3(x-√3) =0
(x-2√3)(x-√3) =0
x = 2√3 or x = √3
Hope it helps.
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