Question

solve the following quadratic equations using formula : (2x + 3) (3x-2) + 2 = 0​

Answer 1

$(2x + 3)(3x - 2) + 2 = 0 \\ \\ = > 6 {x}^{2} - 4x + 9x - 6 + 2 = 0 \\ \\ = > 6 {x}^{2} + \: 5x \: - \: 4 = 0 \\ \\ = >6 {x}^{2} - 3x + 8x - 4 = 0 \\ \\ = > 3x(2x - 1) + 4(2x - 1) = 0 \\ \\ = > (2x - 1) \times (3x + 4) = 0 \\ \\ = > 2x - 1 = 0 \\ = > x = \frac{1}{2} \\ or \\ = > 3x + 4 = 0 \\ = > 3x = - 4 \\ = > x = \frac{ - 4}{3}$