Question

solve the following quadratic equations x^2-4x+13=0​

Answer 1

Hey MATE!!!

We apply Shidharachary formula to solve this quadratic equation :-

D = b^2 -4ac {b = -4,a = 1,c = 13}

D = (-4)^2 - 4(1)(13)

D = 16 - 52

D = -36

Since, Discriminant is negative therefore the roots are imaginary.

$x = \frac{-b ± \sqrt{ D}}{2a} \\ x = \frac{ - ( - 4) ± \sqrt{ - 36} }{2(1)}</em></strong><strong><em> </em></strong><strong><em>\</em></strong><strong><em>\</em></strong><strong><em> </em></strong><strong><em>x </em></strong><strong><em>=</em></strong><strong><em> </em></strong><strong><em>\</em></strong><strong><em>frac</em></strong><strong><em>{</em></strong><strong><em>4</em></strong><strong><em> </em></strong><strong><em>±</em></strong><strong><em> </em></strong><strong><em>\</em></strong><strong><em>sqrt</em></strong><strong><em>{</em></strong><strong><em>-</em></strong><strong><em>3</em></strong><strong><em>6</em></strong><strong><em>}</em></strong><strong><em>}</em></strong><strong><em>{</em></strong><strong><em>2</em></strong><strong><em>}</em></strong><strong><em>$

These are the imaginary roots of the equation.

Hope it helps

Hope it helps HAKUNA MATATA :))

Answer 2

Answer:

Hey mate your answer is here