Question

Solve the following Quadratic Equations :

→ x^2 - 7x + 3 = 0​

Answer 1

Answer:

by which method only incomplete question

Answer 2

Given : $\:\sf{x}^{2}\:-\:7x\:+\:3\:=\:0$

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Here,

$\:\:\:\:\:\:\:\pink\circledcirc\:\sf{a\:=\:1}$

$\:\:\:\:\:\:\:\pink\circledcirc\:\sf{b\:=\:-7}$

$\:\:\:\:\:\:\:\pink\circledcirc\:\sf{c\:=\:3}$

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$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\twoheadrightarrow\:{\underbrace{\underline{\red{\sf{x\:=\:{\dfrac{-b\:\pm{\sqrt{{b}^{2}\:-\:4ac}}}{2a}}}}}}}$

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$\:\:\twoheadrightarrow\sf{\sf{\dfrac{-(-7)\:\pm\:{\sqrt{{(-7)}^{2}\:-\:4\:\times\:1\:\times\:3}}}{2\:\times\:1}}}$

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$\:\:\twoheadrightarrow\:\sf{\dfrac{7\:\pm\:{\sqrt{49\:-\:12}}}{2}}$

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$\:\:\twoheadrightarrow\:\sf{\dfrac{7\:\pm{\sqrt{37}}}{2}}$

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$\:\:\twoheadrightarrow\:\sf{\dfrac{7\:\pm\:6.08}{2}}$

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Taking positive sign,

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$\:\:\twoheadrightarrow\:\sf{x\:=\:{\dfrac{7\:+\:6.05}{2}}\:=\:6.54}$

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Taking negative sign,

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$\:\:\twoheadrightarrow\:\sf{x\:=\:{\dfrac{7\:-\:6.08}{2}}\:=\:0.46}$

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Hence,

$\:\:\:\:\:\:\:\:\:\:\:\therefore\:{\underline{\sf{The\:Value\:of\:x\:is\:{\frak{\purple{6.54}}\:{\sf{and\:{\frak{\purple{0.46}}}}}}}}}.$

${ }$