Question

solve the following quadratics equation 4x2+1=0​

Answer 1

step by step explanation

Given as 4x² + 1 = 0

+ 1 = 0As we know, i² = –1 ⇒ 1 = –i²

On substituting 1 = –i2 in the above equation,

On substituting 1 = –i2 in the above equation, we get 4x² – i2 = 0 (2x)² – i² = 0

= 0[On using the formula, a² – b² = (a + b) (a – b)]

= (a + b) (a – b)] (2x + i) (2x – i) = 0

= (a + b) (a – b)] (2x + i) (2x – i) = 0 2x + i = 0 or 2x – i = 0

= (a + b) (a – b)] (2x + i) (2x – i) = 0 2x + i = 0 or 2x – i = 0 2x = –i or 2x = i

= (a + b) (a – b)] (2x + i) (2x – i) = 0 2x + i = 0 or 2x – i = 0 2x = –i or 2x = i x = -i/2 or x = i/2

= (a + b) (a – b)] (2x + i) (2x – i) = 0 2x + i = 0 or 2x – i = 0 2x = –i or 2x = i x = -i/2 or x = i/2 ∴ The roots of the given equation are i/2, -i/2 .

I hope it is understandable.....

thanks