Math, asked by dakshmalhotra21, 9 months ago

Solve the following quadrative polynomial by factorization (2x-3)(3x-7)=0

Answers

Answered by pari089
0

Answer:

Hi please mark my answers as brain list

Answered by kanthi36940
1

Answer:

(2x-3)(3x-7)=0

Step-by-step explanation:

After multiplying both the terms we get

6x^2-9x-14x+21

consider 6x^2-9x

taking 3x common we get 3x(2x-3)

now consider -14x+21

taking 7 common we get 7(2x-3)

we can write them as (3x-7)(2x-3)

we get x=7/3 and x = 3/2

this is the answer hope u r satisfied

please mark as brainlist

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