Solve the following quadrative polynomial by factorization (2x-3)(3x-7)=0
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Answer:
(2x-3)(3x-7)=0
Step-by-step explanation:
After multiplying both the terms we get
6x^2-9x-14x+21
consider 6x^2-9x
taking 3x common we get 3x(2x-3)
now consider -14x+21
taking 7 common we get 7(2x-3)
we can write them as (3x-7)(2x-3)
we get x=7/3 and x = 3/2
this is the answer hope u r satisfied
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