Math, asked by simran814691, 9 months ago

solve the following quadric equation
1. y^2-4y+3=0
2. z^2-32z-105=0
3.6-x-x^2=0
4.m^2-17mn-84n^2=0
5.5x^2+15x+3=0
6.6x^2+17x+12=0
7.9x^2+18x+8=0
8.14x^2+9x+1=0​

Answers

Answered by mhanifa
0

Answer:

1. y^2-4y+3=0

y = 3 ,  y = 1

2. z^2-32z-105=0

z = 35 ,  z = -3

3.6-x-x^2=0

x = 2 ,  x = -3

4. m^2-17mn-84n^2=0

m= 21n, m= -4n

5. 5x^2+15x+3=0

x= -2.785, x= -0.215

6. 6x^2+17x+12=0

x = -1.500 ,  x = -1.333

7. 9x^2+18x+8=0

x= 1.333, x= -0.667

8. 14x^2+9x+1=0​

x= -0.5, x= -0.143

Answered by ankit0000027
0

Answer:

sorry but i have to do another work thats why i have done only 4

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