solve the following quartic equation by completing the square method
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where is the question bro
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samaz lo
Example 1: Solve x2 + 4x + 1 = 0
Step 1 can be skipped in this example since the coefficient of x2 is 1
Step 2 Move the number term to the right side of the equation:
x2 + 4x = -1
Step 3 Complete the square on the left side of the equation and balance this by adding the same number to the right side of the equation.
(b/2)2 = (4/2)2 = 22 = 4
x2 + 4x + 4 = -1 + 4
(x + 2)2 = 3
Step 4 Take the square root on both sides of the equation:
x + 2 = ±√3 = ±1.73 (to 2 decimals)
Step 5 Subtract 2 from both sides:
x = ±1.73 – 2 =
mark brainliest ans
Example 1: Solve x2 + 4x + 1 = 0
Step 1 can be skipped in this example since the coefficient of x2 is 1
Step 2 Move the number term to the right side of the equation:
x2 + 4x = -1
Step 3 Complete the square on the left side of the equation and balance this by adding the same number to the right side of the equation.
(b/2)2 = (4/2)2 = 22 = 4
x2 + 4x + 4 = -1 + 4
(x + 2)2 = 3
Step 4 Take the square root on both sides of the equation:
x + 2 = ±√3 = ±1.73 (to 2 decimals)
Step 5 Subtract 2 from both sides:
x = ±1.73 – 2 =
mark brainliest ans
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