solve the following question:- 0.25(4f-3)=0.05(10f-9) this is a sum from maths chapter 2 class 8
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0.25(4f-3)=0.05(10f-9)
1f-0.75=0.50f-0.45
1f-0.05f=0.50-0.45
0.95f=0.05
f=0.05/0.95
f=5/100×100/95
f=19
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