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angle A=Angle C =60 (opp.angles of parallelogram are equal)
In triangle DCB
Angle D+Angle C+Angle B=180 (Angle sum property )
Angle D+60+80=180
Angle D=40
so angle CDB=40
In triangle DCB
Angle D+Angle C+Angle B=180 (Angle sum property )
Angle D+60+80=180
Angle D=40
so angle CDB=40
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Angle DAB = 60°
angle ABD = 80°
Angle DAB + ABC = 180° ( sum of adjacent angles of a parallelogram)
Angle ABD = 40°
Angle CDB = ABD (alternate angles)
Angle CBD = 40°
angle ABD = 80°
Angle DAB + ABC = 180° ( sum of adjacent angles of a parallelogram)
Angle ABD = 40°
Angle CDB = ABD (alternate angles)
Angle CBD = 40°
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