Question

solve the following Question ​

Answer 1

Answer:

Here is your solution of your question

Step-by-step explanation:

$p(x) = 3 {x}^{2} - 1$

$putting \: x = \frac{ - 1}{ \sqrt{3} }$

$p( \frac{ - 1}{ \sqrt{3} } ) = 3( \frac{ - 1}{ \sqrt{3} } ) {}^{2} - 1$

$= 3( \frac{1}{3} ) - 1$

$= \frac{3}{3} - 1$

= 1 - 1

= 0

$now \: putting \: x = \frac{2}{ \sqrt{3} }$

$p( \frac{2}{ \sqrt{3} } ) = 3( \frac{2}{ \sqrt{3} } ) {}^{2} - 1$

$= 3( \frac{4}{3} ) - 1$

= 4 - 1

= 3