Question

Solve the following question :- 4x+2/8x+3=3x+1/6x+3

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\frac{4x + 2}{8x + 3} = \frac{3x + 1}{6x + 3}$

$(4x + 2)(6x + 3) = (3x + 1)(8x + 3)$

$2(2x + 1) \times 3(2x + 1) = (3x + 1)(8x + 3)$

$6(2x + 1) {}^{2} = 24x {}^{2} + 8x + 9x + 3$

$6(4x {}^{2} + 4x + 1) = 24x {}^{2} + 17x + 3$

$24x {}^{2} + 24x + 6 = 24 {x}^{2} + 17x + 3$

$7x = - 3$

$x = - \frac{3}{7}$