Math, asked by ghioyyu, 1 year ago

solve the following question

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Answered by Anonymous
5
Ramesh will buy the selected shirt
 \frac{88}{100}  \\  =  \frac{22}{25}
Kewal will buy the selected shirt

 =  \frac{96}{100}   \\  =  \frac{24}{25}
Answered by Krais
2

Answer:


Step-by-step explanation:

1) let the cons odd nos be x and x+2.

Reciprocal = 1/x and 1/x+2

Sum of reciprocal = 12/35

➡️ 1/x + 1/x+2 = 12/35

➡️ x+2 + x/x(x+2) = 12/35

➡️ 2x+2/x^2 + 2x = 12/35

➡️ 35(2x + 2) = 12(x^2 + 2x)

➡️70x + 70 = 12x^2 + 24x

➡️ 70 = 12x^2 +24x - 70x

➡️ 12x^2 - 46x - 70 =0

➡️ 6x^2 - 23x - 35 = 0

➡️ 6x^2 - 30x + 7x - 35 = 0

➡️ 3x(x-5) + 7(x-5) = 0

➡️ 3x+7)(x-5) = 0

➡️ X= - 7/3 or x = 5

➡️ X cant be - 7/3 so x = 5.

Hence nos are 5,and 5 +2 = 7

So required nos are 5 and 7.


2) i) p (ramesh buys) = 88/100

➡️ P (ramesh buys) = 22/25

(ii) P (kewal buys) = 100-4/100

P (kewal buys) = 96/100 = 24/25

Hence probability are 22/25 and 24/25 respectively.


Krais: Pls mark my answer as brainliest
Krais: Thanks
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