solve the following question. (Any one)
Show that the points (2.0), (-2, 0) and (0, 2) are the vertices of a triangle. Also state with
reason the type of the triangle.
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Step-by-step explanation:
let the points are A(2,0),B(-2,0) and C(0,2)
Distance between A and B
=√{(x2-x1)²+(y2-y1)²}
=√{(-2-2)²+(0-0)²}
=√(4²+0²)
=√(16+0)
=4
Distance between B and C
=√{(x2-x1)²+(y2-y1)²}
=√{(0-(-2))²+(2-0)²}
=√{(0+2)²+2²}
=√(2²+2²)
=√(16+16)
=4√2
Distance between A and C
=√{(x2-x1)²+(y2-y1)²}
=√{(0-2)²+(2-0)²}
=√(2²+2²)
=√(4+4)
=√8
=2√2
4+2√2>4
so it is a triangle
it is an scalene triangle.
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