solve the following question :-
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Answered by
4
hey... here's ur solution !!
Substitute,
1 / √x = X. and. 1 / √ y. = Y
2X + 3Y = 2...........................(1)
4X + 9Y = -1...........................(2)
multi eq. (1) by 3 ,
6X + 9Y = 6.............................(3)
adding equ. (3) and eq (2) ,
we get,
10X = 5
X = 1/2
now,
1 / √ x = 1/ 2
➡ x = 4
Now,
3Y = 2- 2X
➡2 - 2( 1/2 )= 1
Y = 1/3➡ 1/ √ y. = 1/3
➡ y = 9
Thus,
x = 4 , y = 9 is the solution
HOPE IT MIGHT BE HELPFUL :)
Substitute,
1 / √x = X. and. 1 / √ y. = Y
2X + 3Y = 2...........................(1)
4X + 9Y = -1...........................(2)
multi eq. (1) by 3 ,
6X + 9Y = 6.............................(3)
adding equ. (3) and eq (2) ,
we get,
10X = 5
X = 1/2
now,
1 / √ x = 1/ 2
➡ x = 4
Now,
3Y = 2- 2X
➡2 - 2( 1/2 )= 1
Y = 1/3➡ 1/ √ y. = 1/3
➡ y = 9
Thus,
x = 4 , y = 9 is the solution
HOPE IT MIGHT BE HELPFUL :)
pangtirajput:
ty sisso
Answered by
1
Let from the question
1/root x = a and 1/root y = b
Then the equation becomes
2a + 3b = 2 -------(1)
4a - 9b = -1 -------(2)
__________________________
Solving (1) and (2)
(1) × 2 》4a + 6b = 4
(2) × 1 》4a - 9b = -1
(-) (+) (+)
________________
15 b = 5
________________
b = 1/3
Then 2a + 3b = 2
2a + 3(1/3) = 2
2a = 2-1
a = 1/2
_________________________
From this a = 1/2 and b = 1/3
Then 1/root x = a
》x = (3)^2 = 9
Also 1/root y = b
》y = (2)^2 = 4
________________________
Hence x = 9 and y = 4
☺ Hope this Helps ☺
1/root x = a and 1/root y = b
Then the equation becomes
2a + 3b = 2 -------(1)
4a - 9b = -1 -------(2)
__________________________
Solving (1) and (2)
(1) × 2 》4a + 6b = 4
(2) × 1 》4a - 9b = -1
(-) (+) (+)
________________
15 b = 5
________________
b = 1/3
Then 2a + 3b = 2
2a + 3(1/3) = 2
2a = 2-1
a = 1/2
_________________________
From this a = 1/2 and b = 1/3
Then 1/root x = a
》x = (3)^2 = 9
Also 1/root y = b
》y = (2)^2 = 4
________________________
Hence x = 9 and y = 4
☺ Hope this Helps ☺
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