solve the following question
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hey.. Mate here's ur solution,
We know that,
sec ( 90 - Φ ) = cosec Φ ,
tan ( 90 -Φ ) = cot Φ
cot (90 - Φ ) = tan Φ
cosec ( 90 - Φ ) = sec Φ
hence,
( Use attachment )
hence
1 - 1 = 0
hope it might be helpful !!
We know that,
sec ( 90 - Φ ) = cosec Φ ,
tan ( 90 -Φ ) = cot Φ
cot (90 - Φ ) = tan Φ
cosec ( 90 - Φ ) = sec Φ
hence,
( Use attachment )
hence
1 - 1 = 0
hope it might be helpful !!
Attachments:
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