solve the following question please
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16° is ur answer.................
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angleACB + angleABC +angleBAC=180
angleBAC=180-65-33
=82'
angle BAN=1/2×82 (becauseAN bisect A)
=41'
In triangle ABM
angleABM + angleAMB+angleBAM=180
angleBAM=180-65-90
=25
angleMAN=angleBAN-angleBAM
=41-25
=16'
angleBAC=180-65-33
=82'
angle BAN=1/2×82 (becauseAN bisect A)
=41'
In triangle ABM
angleABM + angleAMB+angleBAM=180
angleBAM=180-65-90
=25
angleMAN=angleBAN-angleBAM
=41-25
=16'
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