solve the following question with explanation.
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diameter of the circle = 6cm
radius of the circle = 6/2 = 3cm
length of the tangents = 4cm
in ∆AOB
(OB)^2 = (OA)^2 +(AB)^2
x^2 = 3^2 + 4^2
x^2 = 9 + 16
x = √25
x = 5
therefore the distance between the point and the centre = 5cm
i think this is the answer...........I hope this helps u
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