Question

solve the following question=
x^2+6√2x+10​

Answer 1

Answer:

$x = \frac{ - 6 \sqrt{2} + \sqrt{112} }{2} \\ x = \frac{ - 6 \sqrt{2} - \sqrt{112} }{2}$

Step-by-step explanation:

$Given, \\ x {}^{2} + 6 \sqrt{2} x - 10 \\ On \: comparing \: to \: the \: standard \: form ax {}^{2} + by + c = 0 \\ we \: get \: a = 1 \: b = 6 \sqrt{2} \: c = - 10 \\ By \: Quadratic \: Equation \: Formula, \\ x = \frac{ - b + - \sqrt{b {}^{2} - 4ac } }{2a} \\ x = \frac{ - 6 \sqrt{2} + - \sqrt{(6 \sqrt{2}) {}^{2} - 4(1)( - 10)} }{2(1)} \\ = x = \frac{ - 6 \sqrt{2} + - \sqrt{36 \times 2 + 40} }{2} \\ = x = \frac{ - 6 \sqrt{2} + - \sqrt{72 + 40} }{2} \\ = x = \frac{ - 6 \sqrt{2} + - \sqrt{112} }{2} \\ Therefore \: x = \frac{ - 6 \sqrt{2} + \sqrt{112} }{2} \\ x = \frac{ - 6 \sqrt{2} - \sqrt{112} }{2}$

Hope this will help you!!