Question

Solve the following question
x - y - x² + y²​

Answer 1

Answer:

$x - y - x { }^{2} + y {}^{2} \\ (x - y) - (x {}^{2} - y {}^{2} ) \\ (x - y) - (x + y)(x - y) \\ x - y - x - y + x - y \\ x - 3y = 0$

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Answer 2

The answer of this question is $(x-y)[1-x-y]$ .

Step-by-step explanation:

We are given,

$x-y-x^{2} +y^{2}$

and we have to solve this given equation.

• Formula used,

$(a^{2} -b^{2} )=(a-b)(a+b)$

• Solving given equation

we have,

$x-y-x^{2} +y^{2}$

by using formula, we get

$(a^{2} -b^{2} )=(a-b)(a+b)$

but according to question we have $a=x$  and  $b=y$ ,

$x-y-(x^{2} -y^{2} )$

$x-y-[(x-y)(x+y)]$

$(x-y)-(x-y)(x+y)$

taking $(x-y)$ common

$(x-y)[1-(x+y)]$

$(x-y)[1-x-y]$

we get the answer of this question as $(x-y)[1-x-y]$.