Question

Solve the following questions:
1. A wire carries a current of 0.2 A for 10 seconds. If the potential difference between the two
ends of the wire is 20 V, find the work done in this process.​

Answer 1

Answer:

40 J .

Explanation:

Given :

Current ( I )  = 0.2 A

Time ( t ) = 10 sec

Potential difference ( V )  = 20 V

We have to find work done.

Work done ( H ) = I² R t

In order to find R , we have ohm's law

V = I R

R =  20 / 0.2  Ω

R =  100  Ω

Now for work done :

H = 0.2 × 0.2 × 100 × 10 J

H = 2 × 2 × 10 J

H = 40 J

Hence work done is 40 J .

Answer 2

SOLUTION:-

Given:

Current, (I)= 0.2Ampere,

Time, (t)= 10 seconds

Potential difference (V)= 20

So,

Work Done:

We know that formula of work is,

Work= Voltage × Current× time

=) Work= 20 × 0.2 × 10

=) Work= 20 × 2

=) Work = 40 Joule

Thus, work required is 40 joule.

Hope it helps ☺️