Math, asked by parishma87, 10 months ago

Solve the following questions​

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Answered by davadas
1

Answer:

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Answered by mpragati8860
1

Answer:

SECTION A

Step-by-step explanation:

1)    5/12 AND 11/12

2)    a)  69

      b)  39

3)    4

SECTION B

1)    

    a)  49  = XLIX

    b)  51  = LI

2)   NO,35 and 99 are not coprime numbers.

SECTION C

 

2)  

   a)  6000000+200000+20000+8000+400+30+7

   b)  4072436

3)     2038+473182 = 475220

      475220+6225281 = 6700501

4)   2425 multiply 1367 =3314975        (sign is not available)

5)  e e

      a)  51 9

      because it is the largest one digit number that can be used and the                

       sum 5+1+9 =15 is also divisible by 3.

      b) 53 91

      same  as above question the same reason is there and sum is 5+3+9+1      

       =18.

      c) 6720

        same reason and sum is 6+7+2+0 =15

 6)  3528 = 2*2*2*3*3*7*7

 SECTION D

 

  2)   RULE for 2= last digit should be even .

        Rule for 3 = sum should be divisible by 3.

        Rule for 4 = last 2 digits should be divisble by 4.

        Rule for 5 = last digit should be 0 or 5.

        Rule for 10 = last digit should be 0.

sry the last question is not able to be send .

 pleae give brainliest for solving this question.

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