Question

solve the following questions​

Answer 1

4y =6.3 + 1.9

4y=8.2

4y=8.2/4

y=2.05

Answer 2

$\large\sf\underline{Given\::}$

• $\sf\:4y-1.9=6.3$

‎

‎

$\large\sf\underline{To\:find\::}$

• Value of y = ?

‎

‎

$\large\sf\underline{Solution\::}$

$\sf\:4y-1.9=6.3$

‎

• Let's convert decimal number in fraction form

‎

$\sf\implies\:4y-\frac{19}{10}=\frac{63}{10}$

‎

• Now finding LCM of 1 and 10 in LHS

‎

$\sf\implies\:\frac{(4y \times 10) - 19}{10}=\frac{63}{10}$

‎

• Multiplying the terms in LHS

‎

$\sf\implies\:\frac{40y - 19}{10}=\frac{63}{10}$

‎

• Now Cross multiplying

‎

$\sf\implies\:10(40y - 19)=63 \times 10$

‎

• Multiplying and removing brackets

‎

$\sf\implies\:400y - 190=630$

‎

• Transposing -190 to RHS it becomes +190

‎

$\sf\implies\:400y =630+190$

$\sf\implies\:400y = 820$

‎

• Transposing 400 to RHS it goes to denominator

‎

$\sf\implies\:y = \frac{82\cancel{0}}{40\cancel{0}}$

$\sf\implies\:y = \cancel{\frac{82}{40}}$

$\sf\implies\:y = \frac{41}{20}$

$\small\fbox\red{★\:y\:=\:2.05}$

‎

‎ =============================

$\large\sf\underline{Verifying\::}$

$\sf\:4y-1.9=6.3$

‎

• Substituting the value of y as 2.05

‎

$\sf\leadsto\:4(2.05)-1.9=6.3$

‎

• Multiplying and removing brackets

‎

$\sf\leadsto\:8.2-1.9=6.3$

‎

• Subtracting the terms

‎

$\sf\leadsto\:6.3=6.3$

$\dag\:\underline{\sf Hence\:Verified}$

‎

=============================

‎

!! Hope it helps !!