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Q. 9
4.2
( 51 Votes )
Divide a rope of
Class 9th
MHB - Math Part-I
5. Linear Equations in Two Variables
Answer
Let the length of smaller part be 'x' cm and larger part be 'y' cm.
Length of rope = 560 cm
⇒ x + y = 560
⇒ y = 560 - x eq.[1]
Also,
Twice the length of smaller part is equal to
of the larger part
⇒ 6x = y
⇒ 6x = 560 - x
⇒ 7x = 560
⇒ x = 80
Using this in eq.[1]
⇒ y = 560 - 80 = 480
Therefore,
Length of smaller part = 'x' cm = 80 cm
Length of larger part = 'y' cm = 480 cm
Answer:
let the length of smaller part be the rope be 'x' cm and that of larger part be 'y'
According to 1st condition ,
the total length of rope is 560cm ..(i)
twice the length of the larger part= 1/3 y
According to 2nd condition,
2x=1/3×3
•6x=y
•6x-y=0...(ii)
Adding equations (i) n (ii)
•x=560/7
•x=80
substituting x=80 in equation(ii)
6x-y=0
•6(80)-y=0
•y=480
● the length of larger part of rope is 480 cm
here's your answer....