Math, asked by navsan, 1 year ago

solve the following questions

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Answers

Answered by saood3567
0
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Answered by sonalikanayakapr30
0

Answer:

Step-by-step explanation:

answer to your 1st question is -

abc +10^x/(100)^1/2x=0.000abc

>abc(1-0.0001)=10^2/2x-10^x

>abc=10^1/x-10^x (1-0.0001=1 as 0.0001 is negligible)

>log abc=log 10^1/x - log 10^x

>log abc=1/x-x

>(log abc)^2=(1/x-x)^2

>1/x^2+x^2-2=(log abc)^2

>1/x^2+x^2=(log abc)^2+2

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