Question

Solve the following questions ​

Answer 1

TanA-CotA = a

a² + 4 = (TanA-Cot)² + 4

= Tan²A+Cot²A-2TanACotA + 4

= Tan²A+Cot²A-2 + 4

a² + 4 = Tan²A+Cot²A+2---------------------------(1)

sinA+CosA = b

b²-1 = Sin²A+Cos²A-2SinACosA-2

= 1-2-2SinACosA

b²-1 = -(1+2SinACosA)-------------------------------(2)

Multiply 1 and 2

(a² + 4)(b²-1) = 4

Tan²A+Cot²A+2[-(1+2SinACosA)] = 4

LHS = Sin⁴A+Cos⁴A/Sin²ACos²A + 2[-(1+2SinACosA)]

(Sin²A+Cos²A)²/Sin²ACos²A +2 [-(1+2SinACosA)]

1/Sin²ACos²A +2 [-(1+2SinACosA)]

Sec²ACosec²A+2[-(1+2SinACosA)]

This cannot be further solved, I tried my best but I think this has some errors. Please get it confirmed by your teacher. Show them the above steps and then ask for any help.

Answer 2

HIII..

GOOD MORNING:-)

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