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Given x=2+√3---(1)
ii)1/x=1/(2+√3)
Rationalising the denominator,weget
=(2-√3)/[(2+√3)(2-√3)]
=(2-√3)/[2²-(√3)²]
= (2-√3)/(4-3)
= (2-√3)----(2)
iii)x+1/x
=2+√3+2-√3
=4----(3)
Now ,
x²+1/x²
=(x+1/x)²-2
=4²-2
=16-2
=14
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