Question

Solve the following questions.
A bag contains 4 yellow and 2 blue balls. One ball is drawn at random. Find the probability
that it is not blue.​

Answer 1

answer:

4/6 =2/3

hope it is useful

Answer 2

Answer:

$\frac{2}{3}$ is the required answer

Step-by-step explanation:

Therefore, the total number of possibilities = 4 + 2 = 6

As, any one ball is picked any ball randomly

so , number of possibilities that it will not be blue = number of yellow balls = 4

therefore, possibility of not getting a blue ball = number of possibilities of not having blue ball / total number of possibilities

so it is = $\frac{4}{6}$ = $\frac{2}{3}$