Question

Solve the following questions. (Any two)
A chord of length 10 cm is at a distance of 12 cm from the centre of the circle. Find the radius
of that circle.
please answer urgent
step by step explanation required​

Answer 1

Answer:

The distance between the centre and a chord of a circle is Perpendicular to the circle. And, the perpendicular from the centre to a chord bisects the chord.

Let the center of the circle be O, diameter be AOB and the given chord be CD = 10cm. Let OP perpendicular to CD.

Then, CP = 1/2 × CD = 5cm, and OP = 12cm. Join radius OC.

Consider triangle COP. It is a right angles triangle with angle CPO = 90°.

So, by Pythagoras Theorem, we have

OC² = OP² + CP²

=> OC² = 5² + 12²

=> OC² = 25 + 144

=> OC² = 169

=> OC = root(169)

=> OC = 13

Hence, radius of the circle is 13 cm