Solve the following questions. (Any two)
Product of Pragati's age 2 years ago and 3 years hence is 84. Find her present age.
Answers
Step-by-step explanation:
Given:-
Product of Pragati's age 2 years ago and 3 years hence is 84.
To find:-
Find her present age ?
Solution:-
Let the present age of Pragathi be X years
Age of Pragathi 2 years ago = (X-2) years
Age of Pragathi 3 years hence = (X+3) years
Their product = (X-2)(X+3) years
=> X(X+3)-2(X+3)
=> X^2+3X-2X-6
=>X^2 + X-6
According to the given problem
Product of Pragati's age 2 years ago and 3 years hence is 84.
=> X^2 + X - 6 = 84
=> X^2+X-6-84 = 0
=>X^2+X-90 = 0
=>X^2+10X-9X-90 = 0
=>X(X+10)-9(X+10) = 0
=> (X+10)(X-9) = 0
=>X+10 = 0 or X-9 = 0
=> X = -10 or X= 9
Age can not be negative
Therefore , X = 9 years
Age of Pragathi = 9 years
Answer:-
Preasent age of Pragathi = 9 years
Check:-
Pragathi age = 9 years
2 years ago her age = 9-2=7 years
3 years hence her age = 9+3=12 year
Their product = 7×12 = 84 years
Verified the given relations.