Solve the following questions. Each question carries 2 marks.
a) In the Fig. 1, square ABCD is extended to form rectangle AEFD.
Prove that EF = AB.
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In squre ABCD, AB = AD......(i)
and in the rectangle AEFD , AD = EF [the opposite sight of a rectangle] ......(ii)
from (i) and (ii) we get by comparing the value of AD,
AB = EF (proved)
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