Math, asked by saishree07, 10 months ago

solve the following questions​
find the products

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Answered by Jermany
5

Step-by-step explanation:

(c + 2)(c+3/5) = c(c + 3/5) + 2(c + 3/5)

= c² + 3c/5 + 2c + 6/5

= c² + 13c/5 + 6/5

(t+4/3)(t+1/3) = t(t+1/3) + 4/3(t+1/3)

= t² + t/3 + 4t/3 + 4/3

= t² + 5t/3 + 4/3

(c-5)(c+1) = c² + c(-5+1) + (-5) [(x+a)(x+b)= +(a+b)x + ab]

= c² - 5c + c -5

= c² - 4c -5

(b-13)(b+10) = b² + b(-13+10) -130 [same identity as above]

= b² -13b +10b -130

= b² - 3b -130

NOTE : THE GIVEN QUESTIONS CAN BE DONE BY USING IDENTITY OR THE WAY USED IN FIRST TWO PARTS.

(b-6)(b-8) = b² + b(-6-8) + 48

= b² -14b +48

(a-3/5)(a-1/3) = a² + a(-3/5-1/3) + (-3/5) x (-1/3)

= a² + -14a/15 + 1/5

Answered by Anonymous
4

Answer:

Hope it helps you.

..........

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