Solve The Following Questions:-
(i)Find the equation of line passing through (3,2) and perpendicular to the line passing through origin and (2,4).
(ii) Find the equation of line passing through (4,7) and parallel to the line 3x+y+6=0
(iii) Find the equation of line with x-intercept 4 and y-intercept 6.
Answers
Answered by
0
Answer:
The line parallel to 3x+7y+6=0 is 3x+7y+k=0
It passes through (−4,3)
⟹3(−4)+7(3)+k=0
−12+21+k=0
⟹k=−9
So the required equation is 3x+7y−9=0
Similar questions